The Arguement

Throughout the many years of Let's Make A Deal's popularity, mathematicians have been fascinated with the possibilities presented by the "Three Doors" ... and a mathematical urban legend has developed surrounding "The Monty Hall Problem."

A heated debate began when Marilyn Savant published a puzzle in her Parade Magazine column. One of her readers posed the following question: “Suppose you’re on a game show, and you’re given a choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the other doors, opens another door, say No. 3, which has a goat. He then says to you, ‘Do you want to pick door No. 2?’ Is it to your advantage to take the switch?”

Ms. Savant, who’s listed in the Guinness Book of World Records Hall of Fame for “Highest IQ” (228), answered “Yes.” Because of the estimated 10,000 letters she received in response, she published a second article on the subject.

Due to the fervor created by Ms. Savant’s two columns, the New York Times published a large front page article in a 1991 Sunday issue which declared: “Her answer... has been debated in the halls of the C.I.A. and the barracks of fighter pilots in the Persian Gulf. It has been analyzed by mathematicians at M.I.T. and computer programmers at Los Alamos National Laboratory in New Mexico. It has been tested in classes ranging from second grade to graduate level at more than 1,000 schools across the country.”

Most people would expect the chances of winning in both sets of 100 trials to be 1 in 3.

Many people would claim that odds of winning in the second trial is 1 in 2, as only 2 cards are face down

Method

One person put on a bad sportsjacket and dealt three cards face down: 2 jokers, representing the undesirable "zonk" prizes, and the ace of spades, representing a new car.

The second person dressed up as Little BoPeep and chose one of the cards. The dealer then revealed a joker and gave the player an opportunity to choose the other card.

For the first set of 100 trials, the player chose to stick with the original card choice.

For the second set of 100 trials, the player always chose the other face down card. Robert and Karen each took turns and dealer and player.

Player does not change mind after one Joker is revealed

Trial Robert Karen Karen Robert
1 zonk zonk zonk win
2 zonk zonk zonk zonk
3 win win zonk zonk
4 winwin winwin
5 zonk win zonk win
6 zonk win zonk zonk
7 zonk zonk win zonk
8 zonk zonk win win
9 zonk win zonk zonk
10 zonk zonk zonk zonk
11 zonk zonk zonk zonk
12 zonk zonk zonk zonk
13 zonk zonk zonk win
14 zonk zonk zonk zonk
15 win zonk zonk zonk
16 zonk zonk zonk zonk
17 win win win zonk
18 win win win zonk
19 win zonk zonk zonk
20 win zonk zonk zonk
21 win win win zonk
22 win zonk win zonk
23 zonk zonk zonk zonk
24 zonk zonk win zonk
25 win zonk win win
TOTALS
win 10 8 9 6
loose 15 17 16 19

WIN: 33 (33%)
LOOSE: 67 (67%)

Player changes mind after one Joker is revealed

Trial Robert Karen Karen Robert
1 zonk win win zonk
2 win win zonk zonk
3 win win win zonk
4 win win win win
5 zonk win zonk zonk
6 zonk win win win
7 win zonk win win
8 win zonk zonk win
9 zonk zonk win win
10 win zonk win win
11 win win win win
12 win win zonk win
13 win zonk win zonk
14 win win win win
15 zonk win zonk zonk
16 win zonk win win
17 win win zonk win
18 win zonk win win
19 win win zonk win
20 zonk zonk win win
21 zonk win win zonk
22 win zonk win win
23 win win win win
24 win zonk win win
25 win zonk zonk win
TOTALS
win 18 14 17 19
loose 7 11 8 6

WIN: 68 (68%)
LOOSE: 32 (32%)

THE SURPRISE ENDING!

Changing your choice of doors after a "zonk" is revealed will double your chance of winning:

Or, you will win 2 out of 3 times if you choose to change your mind after the dealer reveals where the one of the goats is, because there is a 2 in 3 chance that you picked one of the goats to begin with.

What Monty Hall said...

May 12, 1975

Mr. Steve Selvin Asst. Professor of Biostatistics University of California, Berkeley

Dear Steve:

Thank you for sending me the problem from "The American Statistician."

Although I am not a student of a statistics problems, I do know that these figures can always be used to one's advantage, if I wished to manipulate same. The big hole in your argument of problems is that once the first box is seen to be empty, the contestant cannot exchange his box. So the problems still remain the same, don't they. . . one out of three. Oh, and incidentally, after one is seen to be empty, his chances are no longer 50/50 but remain what they were in the first place, one out of three. It just seems to the contestant that one box having been eliminated, he stands a better chance. Not so. It was always two to one against him. And if you ever get on my show, the rules hold fast for you -- no trading boxes after the selection.

Next time let's play on my home grounds. I graduated in chemistry and zoology. You want to know your chances of surviving with our polluted air and water?

Sincerely, Monty